Required Prior Knowledge

Questions

Simplify

a) \(\frac{3x^{2}+6x}{4x} \)

b) \(\frac{x^{2}-5x+6}{x^{2}+x-6}\)

Solutions

Get Ready

Questions

There are 4 people in a room.

They all shake hands with the other 3 people. How many handshakes take place?

The 4 people now line up to leave the room. How many different ways are there for them to line up?

Solutions

Notes

\(n!\) is read as “\(n\) factorial” and$$n!=n\times\left(n-1\right)\times\left(n-2\right)\times\left(n-3\right)\times\dots\times 2\times 1$$e.g. \(5!=5\times 4\times 3\times 2\times 1=120\).

One of the most useful properties of factorials is that$$n!=n\times\left(n-1\right)!$$e.g. \(5!=5\times 4!\).

By definition, \(0!=1\).

Below is a joke that makes good use of factorials.

Solve \(230-220\times 0.5\).

You might not believe me, but the answer is 5!

Examples and Your Turns

Example

Evaluate \(4!\).

Evaluate$$\frac{10!\times 5!}{7!\times 6!}$$

Evaluate$$\frac{7!}{4!\times 3!}$$

Evaluate $$\frac{5!}{3!}$$

Example

Express as a ratio of factorials$$10\times 9\times 8\times 7$$

Your Turn

Express as a ratio of factorials$$12\times 11\times 10$$

Example

Express as a ratio of factorials$$\frac{10\times 9\times 8\times 7}{4\times 3\times 2\times 1}$$

Your Turn

Express as a ratio of factorials$$\frac{11\times 10\times 9\times 8\times 7}{5\times 4\times 3\times 2\times 1}$$

Example

Simplify \(9!-7!\) by factorising

Your Turn

Simplify \(10!-9!+8!\) by factorising

Example

Simplify$$\frac{\left(n+1\right)!}{\left(n-1\right)!}$$

  • $$\begin{align}\frac{\left(n+1\right)!}{\left(n-1\right)!}&=\frac{\left(n+1\right)n\left(n-1\right)!}{\left(n-1\right)!}\\&=n\left(n+1\right)\end{align}$$

Your Turn

Simplify$$\frac{\left(n+1\right)!+n!}{\left(n-1\right)!}$$

  • $$\begin{align}\frac{\left(n+1\right)!+n!}{\left(n-1\right)!}&=\frac{\left(n+1\right)n\left(n-1\right)!+n\left(n-1\right)!}{\left(n-1\right)!}\\&=\frac{\left(n-1\right)!\left(n\left(n+1\right)+n\right)}{\left(n-1\right)!}\\&=n\left(n+1\right)+n\\&=n^{2}+2n\end{align}$$

Your Turn

Find the value of \(x\in\mathbb{R}\), given that$$\frac{\left(x^{2}-1\right)!}{x^{2}-1}=23!$$

  • $$\begin{align}\frac{\left(x^{2}-1\right)!}{\left(x^{2}-1\right)!}&=\frac{\left(x^{2}-1\right)\left(x^{2}-2\right)!}{\left(x^{2}-1\right)!}\\&=\left(x^{2}-2\right)!\end{align}$$Since this is equal to \(23!\) we have that$$\left(x^{2}-2\right)!=23!\\ \therefore x^{2}-2=23 \\ x^{2}=25 \\ x=\pm 5$$

Your Turn

Show that there are exactly:

a) \(6!\) minutes in \(12\) hours

b) \(10!\) seconds in \(6\) weeks

c) \(8!\) [time units] in \(n\) weeks, where the time unit and value of \(n\) are to be found.

Your Turn

Prove by induction that for \(n\in\mathbb{Z}^{+}\),$$\sum_{r=1}^{n} \frac{r\times 2^{r}}{\left(r+2\right)!}=1-\frac{2^{n+1}}{\left(n+2\right)!}$$

Your Turn

Prove by induction that for \(n\in\mathbb{Z}^{+}\),$$\frac{1}{2!}+\frac{2}{3!}+\frac{3}{4!}+\dots+\frac{n}{\left(n+1\right)!}=1-\frac{1}{\left(n+1\right)!}$$

Your Turn

Prove by induction that for \(n\in\mathbb{Z}^{+}\),$$\sum_{i=1}^{n} \left(i^{2}+1\right)i!=n\left(n+1\right)!$$

Your Turn

Prove by induction that for \(n\in\mathbb{Z}^{+},n\ge 2\),$$\left(2n\right)!>2^{n}\left(n!\right)^{2}$$

Investigation

a) Calculate the value of$$\frac{1}{0!}$$

b) Calculate the value of$$\frac{1}{0!}+\frac{1}{1!}$$

c) Calculate the value of$$\frac{1}{0!}+\frac{1}{1!}+\frac{1}{2!}$$

d) Calculate the value of$$\frac{1}{0!}+\frac{1}{1!}+\frac{1}{2!}+\frac{1}{3!}$$

e) Calculate the value of$$\frac{1}{0!}+\frac{1}{1!}+\frac{1}{2!}+\frac{1}{3!}+\dots +\frac{1}{8!}$$

f) Write the series \(\frac{1}{0!}+\frac{1}{1!}+\frac{1}{2!}+\frac{1}{3!}+\dots +\frac{1}{8!}\) in sigma notation

g) What do you notice about the value of these series as the number of terms increases?

h) Use sigma notation to evaluate the following using your graphical calculator$$\frac{1}{0!}+\frac{1}{1!}+\frac{1}{2!}+\frac{1}{3!}+\dots +\frac{1}{20!}$$

Key Facts

Use this applet to generate a prompt for a Key Fact that you need to know for the course. The idea is that you should KNOW these key facts in order to be able to solve problems.