TL;DR

  • A quadratic sequence is one with a constant second difference.

  • That is the difference of the differences between the terms is always the same.

  • All quadratic sequences have the form \(an^{2}+bn+c\).

  • The value of \(a\) is half the second difference.

  • To find \(b\) and \(c\):

    • subtract \(an^{2}\) from the original sequence;

    • find the \(n\)th term of the remaining linear sequence as \(bn+c\)

A quadratic sequence is one where the second difference is constant.

The second difference is the sequence formed by finding the difference of the first differences.

Example 1 - Determine that \(3,7,13,21,31,…\) is a quadratic sequence.

$$ \begin{array}{rccccccccc} \text{Sequence:} & 3 & & 7 & & 13 & & 21 & & 31 \\ \text{1st Difference:} & & 4 & & 6 & & 8 & & 10 & \\ \text{2nd Difference:} & & & 2 & & 2 & & 2 & & \\ \end{array} $$\(3,7,13,21,31,…\) is a quadratic sequence as the second difference is \(2\).

Example 2 - Determine that \(4,7,14,25,40,…\) is a quadratic sequence.

$$ \begin{array}{rccccccccc} \text{Sequence:} & 4 & & 7 & & 14 & & 25 & & 40 \\ \text{1st Difference:} & & 3 & & 7 & & 11 & & 15 & \\ \text{2nd Difference:} & & & 4 & & 4 & & 4 & & \\ \end{array} $$\(4,7,14,25,40,…\) is a quadratic sequence as the second difference is \(4\).

Example 3 - Determine that \(13,22,37,58,85,…\) is a quadratic sequence.

$$ \begin{array}{rccccccccc} \text{Sequence:} & 13 & & 22 & & 37 & & 58 & & 85 \\ \text{1st Difference:} & & 9 & & 15 & & 21 & & 27 & \\ \text{2nd Difference:} & & & 6 & & 6 & & 6 & & \\ \end{array} $$\(13,22,37,58,85,…\) is a quadratic sequence as the second difference is \(6\).

Example 4 - Determine that \(19,36,51,64,75,…\) is a quadratic sequence.

$$ \begin{array}{rccccccccc} \text{Sequence:} & 19 & & 36 & & 51 & & 64 & & 75 \\ \text{1st Difference:} & & 17 & & 15 & & 13 & & 11 & \\ \text{2nd Difference:} & & & -2 & & -2 & & -2 & & \\ \end{array} $$\(19,36,51,64,75,…\) is a quadratic sequence as the second difference is \(-2\).

Example 5 - Determine that \(3.5,6,9.5,14,19.5,…\) is a quadratic sequence.

$$ \begin{array}{rccccccccc} \text{Sequence:} & 3.5 & & 6 & & 9.5 & & 14 & & 19.5 \\ \text{1st Difference:} & & 2.5 & & 3.5 & & 4.5 & & 5.5 & \\ \text{2nd Difference:} & & & 1 & & 1 & & 1 & & \\ \end{array} $$\(3.5,6,9.5,14,19.5,…\) is a quadratic sequence as the second difference is \(1\).

Example 6 - Determine that \(13,8,5,4,5,…\) is a quadratic sequence.

$$ \begin{array}{rccccccccc} \text{Sequence:} & 13 & & 8 & & 5 & & 4 & & 5 \\ \text{1st Difference:} & & -5 & & -3 & & -1 & & 1 & \\ \text{2nd Difference:} & & & 2 & & 2 & & 2 & & \\ \end{array} $$\(13,8,5,4,5,…\) is a quadratic sequence as the second difference is \(2\).

All quadratic sequences have a general form of \(an^{2}+bn+c\).

The value of \(a\) is half the second difference.

Example 1 - Determine the value of \(a\) for the quadratic sequence \(3,7,13,21,31,…\).

$$ \begin{array}{rccccccccc} \text{Sequence:} & 3 & & 7 & & 13 & & 21 & & 31 \\ \text{1st Difference:} & & 4 & & 6 & & 8 & & 10 & \\ \text{2nd Difference:} & & & 2 & & 2 & & 2 & & \\ \end{array} $$\(3,7,13,21,31,…\) is a quadratic sequence as the second difference is \(2\).
The value of \(a\) is \(1\).

Example 2 - Determine the value of \(a\) for the quadratic sequence \(4,7,14,25,40,…\).

$$ \begin{array}{rccccccccc} \text{Sequence:} & 4 & & 7 & & 14 & & 25 & & 40 \\ \text{1st Difference:} & & 3 & & 7 & & 11 & & 15 & \\ \text{2nd Difference:} & & & 4 & & 4 & & 4 & & \\ \end{array} $$\(4,7,14,25,40,…\) is a quadratic sequence as the second difference is \(4\).
The value of \(a\) is \(2\).

Example 3 - Determine the value of \(a\) for the quadratic sequence \(13,22,37,58,85,…\).

$$ \begin{array}{rccccccccc} \text{Sequence:} & 13 & & 22 & & 37 & & 58 & & 85 \\ \text{1st Difference:} & & 9 & & 15 & & 21 & & 27 & \\ \text{2nd Difference:} & & & 6 & & 6 & & 6 & & \\ \end{array} $$\(13,22,37,58,85,…\) is a quadratic sequence as the second difference is \(6\).
The value of \(a\) is \(3\).

Example 4 - Determine the value of \(a\) for the quadratic sequence \(19,36,51,64,75,…\).

$$ \begin{array}{rccccccccc} \text{Sequence:} & 19 & & 36 & & 51 & & 64 & & 75 \\ \text{1st Difference:} & & 17 & & 15 & & 13 & & 11 & \\ \text{2nd Difference:} & & & -2 & & -2 & & -2 & & \\ \end{array} $$\(19,36,51,64,75,…\) is a quadratic sequence as the second difference is \(-2\).
The value of \(a\) is \(-1\).

Example 5 - Determine the value of \(a\) for the quadratic sequence \(3.5,6,9.5,14,19.5,…\).

$$ \begin{array}{rccccccccc} \text{Sequence:} & 3.5 & & 6 & & 9.5 & & 14 & & 19.5 \\ \text{1st Difference:} & & 2.5 & & 3.5 & & 4.5 & & 5.5 & \\ \text{2nd Difference:} & & & 1 & & 1 & & 1 & & \\ \end{array} $$\(3.5,6,9.5,14,19.5,…\) is a quadratic sequence as the second difference is \(1\).
The value of \(a\) is \(\frac{1}{2}\).

Example 6 - Determine the value of \(a\) for the quadratic sequence \(13,8,5,4,5,…\).

$$ \begin{array}{rccccccccc} \text{Sequence:} & 13 & & 8 & & 5 & & 4 & & 5 \\ \text{1st Difference:} & & -5 & & -3 & & -1 & & 1 & \\ \text{2nd Difference:} & & & 2 & & 2 & & 2 & & \\ \end{array} $$\(13,8,5,4,5,…\) is a quadratic sequence as the second difference is \(2\).
The value of \(a\) is \(1\).

To find the values of \(b\) and \(c\) we start by subtracting \(an^{2}\) from the original sequence to get a new sequence.

Example 1 - Determine the difference table for the quadratic sequence \(3,7,13,21,31,…\).

$$ \begin{array}{rccccccccc} \text{Sequence:} & 3 & & 7 & & 13 & & 21 & & 31 \\ \text{1st Difference:} & & 4 & & 6 & & 8 & & 10 & \\ \text{2nd Difference:} & & & 2 & & 2 & & 2 & & \\ \end{array} $$\(3,7,13,21,31,…\) is a quadratic sequence as the second difference is \(2\).
The value of \(a\) is \(1\).
$$ \begin{array}{r|ccccc} n & 1 & 2 & 3 & 4 & 5 \\ \hline u_n & 3 & 7 & 13 & 21 & 31 \\ an^2 & 1 & 4 & 9 & 16 & 25 \\ \hline u_n - an^2 & 2 & 3 & 4 & 5 & 6 \\ \end{array} $$

Example 2 - Determine the difference table for the quadratic sequence \(4,7,14,25,40,…\).

$$ \begin{array}{rccccccccc} \text{Sequence:} & 4 & & 7 & & 14 & & 25 & & 40 \\ \text{1st Difference:} & & 3 & & 7 & & 11 & & 15 & \\ \text{2nd Difference:} & & & 4 & & 4 & & 4 & & \\ \end{array} $$\(4,7,14,25,40,…\) is a quadratic sequence as the second difference is \(4\).
The value of \(a\) is \(2\).
$$ \begin{array}{r|ccccc} n & 1 & 2 & 3 & 4 & 5 \\ \hline u_n & 4 & 7 & 14 & 25 & 40 \\ an^2 & 2 & 8 & 18 & 32 & 50 \\ \hline u_n - an^2 & 2 & -1 & -4 & -7 & -10 \\ \end{array} $$

Example 3 - Determine the difference table for the quadratic sequence \(13,22,37,58,85,…\).

$$ \begin{array}{rccccccccc} \text{Sequence:} & 13 & & 22 & & 37 & & 58 & & 85 \\ \text{1st Difference:} & & 9 & & 15 & & 21 & & 27 & \\ \text{2nd Difference:} & & & 6 & & 6 & & 6 & & \\ \end{array} $$\(13,22,37,58,85,…\) is a quadratic sequence as the second difference is \(6\).
The value of \(a\) is \(3\).
$$ \begin{array}{r|ccccc} n & 1 & 2 & 3 & 4 & 5 \\ \hline u_n & 13 & 22 & 37 & 58 & 85 \\ an^2 & 3 & 12 & 27 & 48 & 75 \\ \hline u_n - an^2 & 10 & 10 & 10 & 10 & 10 \\ \end{array} $$

Example 4 - Determine the difference table for the quadratic sequence \(19,36,51,64,75,…\).

$$ \begin{array}{rccccccccc} \text{Sequence:} & 19 & & 36 & & 51 & & 64 & & 75 \\ \text{1st Difference:} & & 17 & & 15 & & 13 & & 11 & \\ \text{2nd Difference:} & & & -2 & & -2 & & -2 & & \\ \end{array} $$\(19,36,51,64,75,…\) is a quadratic sequence as the second difference is \(-2\).
The value of \(a\) is \(-1\).
$$ \begin{array}{r|ccccc} n & 1 & 2 & 3 & 4 & 5 \\ \hline u_n & 19 & 36 & 51 & 64 & 75 \\ an^2 & -1 & -4 & -9 & -16 & -25 \\ \hline u_n - an^2 & 20 & 40 & 60 & 80 & 100 \\ \end{array} $$

Example 5 - Determine the difference table for the quadratic sequence \(3.5,6,9.5,14,19.5,…\).

$$ \begin{array}{rccccccccc} \text{Sequence:} & 3.5 & & 6 & & 9.5 & & 14 & & 19.5 \\ \text{1st Difference:} & & 2.5 & & 3.5 & & 4.5 & & 5.5 & \\ \text{2nd Difference:} & & & 1 & & 1 & & 1 & & \\ \end{array} $$\(3.5,6,9.5,14,19.5,…\) is a quadratic sequence as the second difference is \(1\).
The value of \(a\) is \(\frac{1}{2}\).
$$ \begin{array}{r|ccccc} n & 1 & 2 & 3 & 4 & 5 \\ \hline u_n & 3.5 & 6 & 9.5 & 14 & 19.5 \\ an^2 & 0.5 & 2 & 4.5 & 8 & 12.5 \\ \hline u_n - an^2 & 3 & 4 & 5 & 6 & 7 \\ \end{array} $$

Example 6 - Determine the difference table for the quadratic sequence \(13,8,5,4,5,…\).

$$ \begin{array}{rccccccccc} \text{Sequence:} & 13 & & 8 & & 5 & & 4 & & 5 \\ \text{1st Difference:} & & -5 & & -3 & & -1 & & 1 & \\ \text{2nd Difference:} & & & 2 & & 2 & & 2 & & \\ \end{array} $$\(13,8,5,4,5,…\) is a quadratic sequence as the second difference is \(2\).
The value of \(a\) is \(1\).
$$ \begin{array}{r|ccccc} n & 1 & 2 & 3 & 4 & 5 \\ \hline u_n & 13 & 8 & 5 & 4 & 5 \\ an^2 & 1 & 4 & 9 & 16 & 25 \\ \hline u_n - an^2 & 12 & 4 & -4 & -12 & -20 \\ \end{array} $$

Finally, we combine the \(an^{2}\) with the \(n\)th term of the linear sequence we have found.

Example 1 - Determine the \(n\)th term for the quadratic sequence \(3,7,13,21,31,…\).

$$ \begin{array}{rccccccccc} \text{Sequence:} & 3 & & 7 & & 13 & & 21 & & 31 \\ \text{1st Difference:} & & 4 & & 6 & & 8 & & 10 & \\ \text{2nd Difference:} & & & 2 & & 2 & & 2 & & \\ \end{array} $$\(3,7,13,21,31,…\) is a quadratic sequence as the second difference is \(2\).
The value of \(a\) is \(1\).
$$ \begin{array}{r|ccccc} n & 1 & 2 & 3 & 4 & 5 \\ \hline u_n & 3 & 7 & 13 & 21 & 31 \\ an^2 & 1 & 4 & 9 & 16 & 25 \\ \hline u_n - an^2 & 2 & 3 & 4 & 5 & 6 \\ \end{array} $$The \(n\)th term of \(2,3,4,5,6,…\) is \(n+1\).

So the \(n\)th term is \(n^{2}+n+1\).

Example 2 - Determine the \(n\)th term for the quadratic sequence \(4,7,14,25,40,…\).

$$ \begin{array}{rccccccccc} \text{Sequence:} & 4 & & 7 & & 14 & & 25 & & 40 \\ \text{1st Difference:} & & 3 & & 7 & & 11 & & 15 & \\ \text{2nd Difference:} & & & 4 & & 4 & & 4 & & \\ \end{array} $$\(4,7,14,25,40,…\) is a quadratic sequence as the second difference is \(4\).
The value of \(a\) is \(2\).
$$ \begin{array}{r|ccccc} n & 1 & 2 & 3 & 4 & 5 \\ \hline u_n & 4 & 7 & 14 & 25 & 40 \\ an^2 & 2 & 8 & 18 & 32 & 50 \\ \hline u_n - an^2 & 2 & -1 & -4 & -7 & -10 \\ \end{array} $$The \(n\)th term of \(2,-1,-4,-7,-10,…\) is \(-3n+5\).

So the \(n\)th term is \(2n^{2}-3n+5\).

Example 3 - Determine the \(n\)th term for the quadratic sequence \(13,22,37,58,85,…\).

$$ \begin{array}{rccccccccc} \text{Sequence:} & 13 & & 22 & & 37 & & 58 & & 85 \\ \text{1st Difference:} & & 9 & & 15 & & 21 & & 27 & \\ \text{2nd Difference:} & & & 6 & & 6 & & 6 & & \\ \end{array} $$\(13,22,37,58,85,…\) is a quadratic sequence as the second difference is \(6\).
The value of \(a\) is \(3\).
$$ \begin{array}{r|ccccc} n & 1 & 2 & 3 & 4 & 5 \\ \hline u_n & 13 & 22 & 37 & 58 & 85 \\ an^2 & 3 & 12 & 27 & 48 & 75 \\ \hline u_n - an^2 & 10 & 10 & 10 & 10 & 10 \\ \end{array} $$The \(n\)th term of \(10,10,10,10,10,…\) is \(10\).

So the \(n\)th term is \(3n^{2}+10\).

Example 4 - Determine the \(n\)th term for the quadratic sequence \(19,36,51,64,75,…\).

$$ \begin{array}{rccccccccc} \text{Sequence:} & 19 & & 36 & & 51 & & 64 & & 75 \\ \text{1st Difference:} & & 17 & & 15 & & 13 & & 11 & \\ \text{2nd Difference:} & & & -2 & & -2 & & -2 & & \\ \end{array} $$\(19,36,51,64,75,…\) is a quadratic sequence as the second difference is \(-2\).
The value of \(a\) is \(-1\).
$$ \begin{array}{r|ccccc} n & 1 & 2 & 3 & 4 & 5 \\ \hline u_n & 19 & 36 & 51 & 64 & 75 \\ an^2 & -1 & -4 & -9 & -16 & -25 \\ \hline u_n - an^2 & 20 & 40 & 60 & 80 & 100 \\ \end{array} $$The \(n\)th term of \(20,40,60,80,100,…\) is \(20n\).

So the \(n\)th term is \(-n^{2}+20n\).

Example 5 - Determine the \(n\)th term for the quadratic sequence \(3.5,6,9.5,14,19.5,…\).

$$ \begin{array}{rccccccccc} \text{Sequence:} & 3.5 & & 6 & & 9.5 & & 14 & & 19.5 \\ \text{1st Difference:} & & 2.5 & & 3.5 & & 4.5 & & 5.5 & \\ \text{2nd Difference:} & & & 1 & & 1 & & 1 & & \\ \end{array} $$\(3.5,6,9.5,14,19.5,…\) is a quadratic sequence as the second difference is \(1\).
The value of \(a\) is \(\frac{1}{2}\).
$$ \begin{array}{r|ccccc} n & 1 & 2 & 3 & 4 & 5 \\ \hline u_n & 3.5 & 6 & 9.5 & 14 & 19.5 \\ an^2 & 0.5 & 2 & 4.5 & 8 & 12.5 \\ \hline u_n - an^2 & 3 & 4 & 5 & 6 & 7 \\ \end{array} $$The \(n\)th term of \(3,4,5,6,7,…\) is \(n+2\).

So the \(n\)th term is \(\frac{1}{2}n^{2}+n+2\).

Example 6 - Determine the \(n\)th term for the quadratic sequence \(13,8,5,4,5,…\).

$$ \begin{array}{rccccccccc} \text{Sequence:} & 13 & & 8 & & 5 & & 4 & & 5 \\ \text{1st Difference:} & & -5 & & -3 & & -1 & & 1 & \\ \text{2nd Difference:} & & & 2 & & 2 & & 2 & & \\ \end{array} $$\(13,8,5,4,5,…\) is a quadratic sequence as the second difference is \(2\).
The value of \(a\) is \(1\).
$$ \begin{array}{r|ccccc} n & 1 & 2 & 3 & 4 & 5 \\ \hline u_n & 13 & 8 & 5 & 4 & 5 \\ an^2 & 1 & 4 & 9 & 16 & 25 \\ \hline u_n - an^2 & 12 & 4 & -4 & -12 & -20 \\ \end{array} $$The \(n\)th term of \(12,4,-4,12,-20,…\) is \(-8n+20\).

So the \(n\)th term is \(n^{2}-8n+20\).

Sequence 2nd Diff \( an^2 \) \( u_n - an^2 \) \( bn+c \) \(n\)th Term
\( 6, 13, 24, 39, \dots \) \( +4 \)
?
\( 2n^2 \)
?
\( 4, 5, 6, 7 \)
?
\( n+3 \)
?
\( 2n^2+n+3 \)
?
\( 2, 9, 20, 35, \dots \) \( +2 \)
?
\( n^2 \)
?
\( 1, 5, 11, 19 \)
?
\( 4n-3 \)
?
\( n^2+4n-3 \)
?
\( 3, 10, 21, 36, \dots \) \( +4 \)
?
\( 2n^2 \)
?
\( 1, 2, 3, 4 \)
?
\( n \)
?
\( 2n^2+n \)
?
\( 1, 4, 9, 16, \dots \) \( +2 \)
?
\( n^2 \)
?
\( 0, 0, 0, 0 \)
?
\( 0 \)
?
\( n^2 \)
?
\( 10, 22, 40, 64, \dots \) \( +6 \)
?
\( 3n^2 \)
?
\( 7, 10, 13, 16 \)
?
\( 3n+4 \)
?
\( 3n^2+3n+4 \)
?
\( 10, 15, 18, 19, \dots \) \( -2 \)
?
\( -n^2 \)
?
\( 11, 19, 27, 35 \)
?
\( 8n+3 \)
?
\( -n^2+8n+3 \)
?
\( 3, 5.5, 9, 13.5, \dots \) \( +1 \)
?
\( 0.5n^2 \)
?
\( 2.5, 3.5, 4.5, 5.5 \)
?
\( n+1.5 \)
?
\( 0.5n^2+n+1.5 \)
?
\( 5, 2, -5, -16, \dots \) \( -4 \)
?
\( -2n^2 \)
?
\( 7, 10, 13, 16 \)
?
\( 3n+4 \)
?
\( -2n^2+3n+4 \)
?
\( 2, 6.5, 14, 24.5, \dots \) \( +3 \)
?
\( 1.5n^2 \)
?
\( 0.5, 0.5, 0.5, 0.5 \)
?
\( 0.5 \)
?
\( 1.5n^2+0.5 \)
?
\( 4, 3.5, 2, -0.5, \dots \) \( -1 \)
?
\( -0.5n^2 \)
?
\( 4.5, 5.5, 6.5, 7.5 \)
?
\( n+3.5 \)
?
\( -0.5n^2+n+3.5 \)
?

Quadratic \(n\)th Term

Find the \(n\)th term for the quadratic sequence below.